1z0-808日本語試験問題集、1z0-061デモ

 

現在の仕事に満足していますか。自分がやっていることに満足していますか。自分のレベルを高めたいですか。では、仕事に役に立つスキルをもっと身に付けましょう。もちろん、IT業界で働いているあなたはIT認定試験を受けて資格を取得することは一番良い選択です。それはより良く自分自身を向上させることができますから。もっと大切なのは、あなたもより多くの仕事のスキルをマスターしたことを証明することができます。では、はやくOracleの1z0-808日本語試験問題集を受験しましょう。この試験はあなたが自分の念願を達成するのを助けることができます。試験に合格する自信を持たなくても大丈夫です。JPexamへ来てあなたがほしいヘルパーと試験の準備ツールを見つけることができますから。JPexamの資料はきっとあなたが1z0-808日本語試験問題集の認証資格を取ることを助けられます。

Java SE 8 Programmer I

Exam Number: 1Z0-808 / 1Z1-808
Duration: TBD
Associated Certifications: Oracle Certified Associate, Java SE 8 Programmer
Number of Questions: TBD
Exam Product Version: Java SE,
Passing Score: TBD%
Exam Price: US$ 150
Validated Against: This exam has been written for the Java SE 8 release.
format: Multiple Choice

 

Recommended Training

TOPICS

Java Basics
  • Define the scope of variables
  • Define the structure of a Java class
  • Create executable Java applications with a main method; run a Java program from the command line; including console output.
  • Import other Java packages to make them accessible in your code
  • Compare and contrast the features and components of Java such as: platform independence, object orientation, encapsulation, etc.
Working With Java Data Types
  • Declare and initialize variables (including casting of primitive data types)
  • Differentiate between object reference variables and primitive variables
  • Know how to read or write to object fields
  • Explain an Object's Lifecycle (creation, "dereference by reassignment" and garbage collection)
  • Develop code that uses wrapper classes such as Boolean, Double, and Integer.
Using Operators and Decision Constructs
  • Use Java operators; including parentheses to override operator precedence
  • Test equality between Strings and other objects using == and equals ()
  • Create if and if/else and ternary constructs
  • Use a switch statement
Creating and Using Arrays
  • Declare, instantiate, initialize and use a one-dimensional array
  • Declare, instantiate, initialize and use multi-dimensional array
Using Loop Constructs
  • Create and use while loops
  • Create and use for loops including the enhanced for loop
  • Create and use do/while loops
  • Compare loop constructs
  • Use break and continue
Working with Methods and Encapsulation
  • Create methods with arguments and return values; including overloaded methods
  • Apply the static keyword to methods and fields
  • Create and overload constructors; including impact on default constructors
  • Apply access modifiers
  • Apply encapsulation principles to a class
  • Determine the effect upon object references and primitive values when they are passed into methods that change the values
Working with Inheritance
  • Describe inheritance and its benefits
  • Develop code that demonstrates the use of polymorphism; including overriding and object type versus reference type
  • Determine when casting is necessary
  • Use super and this to access objects and constructors
  • Use abstract classes and interfaces
Handling Exceptions
  • Differentiate among checked exceptions, unchecked exceptions, and Errors
  • Create a try-catch block and determine how exceptions alter normal program flow
  • Describe the advantages of Exception handling
  • Create and invoke a method that throws an exception
  • "Recognize common exception classes (such as NullPointerException, ArithmeticExcpetion, ArrayIndexOutOfBoundsException, ClassCastException)"
Working with Selected classes from the Java API
  • Manipulate data using the StringBuilder class and its methods
  • Creating and manipulating Strings
  • Create and manipulate calendar data using classes from java.time.LocalDateTime, java.time.LocalDate, java.time.LocalTime, java.time.format.DateTimeFormatter, java.time.Period
  • Declare and use an ArrayList of a given type
  • Write a simple Lambda expression that consumes a Lambda Predicate expression
1z0-808日本語試験番号：1z0-808日本語問題集
試験科目：Java SE 8 Programmer I (1z0-808日本語版)
最近更新時間：2015-12-29
問題と解答：全77問 1z0-808日本語試験問題集
100％の返金保証。1年間の無料アップデート。

>> 1z0-808日本語試験問題集

 
1z0-061試験番号：1z0-061問題集
試験科目：Oracle Database 12c: SQL Fundamentals
最近更新時間：2015-12-29
問題と解答：全75問 1z0-061デモ
100％の返金保証。1年間の無料アップデート。

>> 1z0-061デモ

 

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NO.1 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. RIGHT OUTER JOIN; LEFT OUTER JOIN
B. JOIN; JOIN
C. FULL OUTER JOIN; FULL OUTER JOIN
D. LEFT OUTER JOIN; RIGHT OUTER JOIN
Answer: A

1z0-061試験スクール

NO.2 In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
A. An error message
B. Abigail Pa
C. Abigail PA
D. Abigail IS
Answer: B

1z0-061必殺問題集

NO.3 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Only statement 2 executes successfully and gives the required result.
B. Only statement 1 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give different results.
D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: D

1z0-061訓練 1z0-061テキスト

NO.4 Examine the structure proposed for the transactions table:
Which two statements are true regarding the creation and storage of data in the above table
structure?
A. The CUST_STATUS column would give an error.
B. The TRANS_VALIDITY column would give an error.
C. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes,
seconds, and fractions of seconds
D. The TRANS_VALIDITY column would have a maximum size of one character.
E. The CUST_STATUS column would store exactly one character.
F. The CUST_CREDIT_LIMIT column would not be able to store decimal values.
Answer: B,E

1z0-061受験料 1z0-061認定テキスト
Explanation:
VARCHAR2(size)Variable-length character data (A maximum size must be specified:
minimum size is 1; maximum size is 4, 000.)
CHAR [(size)] Fixed-length character data of length size bytes (Default and minimum size
is 1; maximum size is 2, 000.)
NUMBER [(p, s)] Number having precision p and scale s (Precision is the total number of
decimal digits and scale is the number of digits to the right of the decimal point; precision
can range from 1 to 38, and scale can range from -84 to 127.)
DATE Date and time values to the nearest second between January 1, 4712 B.C., and
December 31, 9999 A.D.

NO.5 You need to create a table for a banking application. One of the columns in the table has the
following requirements:
1. You want a column in the table to store the duration of the credit period.
2) The data in the column should be stored in a format such that it can be easily added and
subtracted with date data type without using conversion functions.
3) The maximum period of the credit provision in the application is 30 days.
4) The interest has to be calculated for the number of days an individual has taken a credit for.
Which data type would you use for such a column in the table?
A. NUMBER
B. INTERVAL DAY TO SECOND
C. TIMESTAMP
D. DATE
E. INTERVAL YEAR TO MONTH
Answer: B

1z0-061合格体験談 1z0-061トレーニング費用

NO.6 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
D. It produces an error because the AMT_SPENT column contains a null value.
Answer: A

1z0-061対応受験
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.

NO.7 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-c, 2-d, 3-a, and 4-b
B. 1-d, 2-b, 3-a, and 4-c
C. 1-c, 2-a, 3-b, and 4-d
D. 1-a, 2-b, 3-c, and 4-d
Answer: C

1z0-061組織

NO.8 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. Fourth normal form
B. Third normal form
C. First normal form
D. Second normal form
Answer: D

1z0-061信頼度

1z0-808J参考書勉強: http://1z0-808j-pdf.jexam.xyz/i63934.html